C++ Question on Char*.

75 pts.
Tags:
C++
Look at the code below:
#include "stdafx.h"
#include "conio.h"
int _tmain(int argc, _TCHAR* argv[])
{
//Snippet 1
char name[20] = "Some Name";
printf("%sn", name);
name[1] = 'a';
printf("%sn", name);
//Snippet 2
char * name2 = "Some Name";
printf("%sn", name2);
name2[1] = 'a';                 //==>Error Here
printf("%sn", name2);
getch();
return 0;
}
 
 Why we get runtime error from code snippet2?

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  • carlosdl
    This looks like a homework question.
    83,215 pointsBadges:
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  • TomLiotta
    What's the error? (I can guess, but that wouldn't help you.) Tom
    125,585 pointsBadges:
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  • Sirama
    An Access violation Error that comes at runtime!
    75 pointsBadges:
    report

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