– Gives list ranked by Country-City-restaurant count
– Ordered by country-rank-city
–
SELECT P1.COUNTRYNAME,P1.CITYNAME
, P1.REST_CNT
, P3.REST_CNT AS RANK
FROM (
SELECT CO.COUNTRYID
, CO.COUNTRYNAME
, CI.CITYID
, CI.CITYNAME
, COUNT(R.RESTAURANTID) AS REST_CNT
FROM RESTAURANT R
JOIN COUNTRY CO
ON R.COUNTRYID=CO.COUNTRYID
JOIN CITY CI
ON R.CITYID=CI.CITYID
WHERE R.ISACTIVE=1
GROUP BY CO.COUNTRYID
, CO.COUNTRYNAME
, CI.CITYID
, CI.CITYNAME
) P1
, TABLE (
SELECT COUNT(DISTINCT P2.REST_CNT) AS REST_CNT
FROM (
SELECT CO.COUNTRYID
, CI.CITYID
, COUNT(R.RESTAURANTID) AS REST_CNT
FROM RESTAURANT R
JOIN COUNTRY CO
ON R.COUNTRYID=CO.COUNTRYID
JOIN CITY CI
ON R.CITYID=CI.CITYID
WHERE R.ISACTIVE=1
GROUP BY CO.COUNTRYID
, CI.CITYID
) P2
WHERE P2.REST_CNT >= P1.REST_CNT
AND P2.COUNTRYID = P1.COUNTRYID
) AS P3
WHERE P3.REST_CNT

create view citycounts
as
select co.countryname
, ci.cityname
, count(r.restaurantid) as restaurants
from restaurant r
inner
join country co
on r.countryid=co.countryid
inner
join city ci
on r.cityid=ci.cityid
where r.isactive=1
group
by co.countryname
, ci.cityname

select countryname
, cityname
, restaurants
from citycounts as x
where restaurants
in ( select top 3
restaurants
from citycounts
where countryname = x.countryname )

Thanks to you all so far! I have been testing all those queries you have sent except the last one from Julius. At the moment I’m not able to access to the server but I will test it as soon as possibe. Sorry btw for the delay in this answer, whole easter has been busy!

Those queries have not given the correct result but they have also given some ideas on how to proceed. Let’s see how this goes tomorrow!

I use Ms Sql Server btw.

Thanks,

Ronjar

select co.countryname, ci.cityname, r.restaurantcount
from city as ci
inner join (select top 3 countryid, cityid,
count(*) as restaurantcount
from restaurant
where isactive = 1
group by countryid, cityid
order by count(*) desc) as r
on ci.cityid = r.cityid
inner join country as co
on r.countryid = co.countryid

Hope it’s work.

;o)

you guys keep forgetting that ronjar did not mention which database he or she is using

therefore, in my opinion (with which you may freely disagree), you should not propose non-standard solutions involving proprietary syntax like TOP or ROWNUM

my solution is standard SQL only

You should use a WHILE statement or an EXIST clause to force a nested query (to get top 3 cities) to run for each country you want.

select c.county_name,
l.city_name,
y.registrations
from location_code l,
entpr.county c,
(
select county_code,
min(row_num) min_row
from (
select c.county_code,
r.city_code,
r.registrations,
rownum row_num
from (
select county_code,
city_code,
count(*) registrations
from regular_registration
where transaction_id is not null
group by
county_code,
city_code) r,
county c
where c.county_code = r.county_code
order by
c.county_code,
r.city_code,
r.registrations desc)
group by
county_code) x,
(
select c.county_code,
r.city_code,
r.registrations,
rownum row_num
from (
select county_code,
city_code,
count(*) registrations
from regular_registration
where transaction_id is not null
group by
county_code,
city_code) r,
county c
where c.county_code = r.county_code
order by
c.county_code,
r.city_code,
r.registrations desc) y
where x.county_code = y.county_code
and y.row_num – x.min_row

Something like
select cityname, cityid from city-table where cityid = (select county(esturauntid), cityid from resturaunt-table TOP 3)

Actually, the problem I see with this is that there will never be a matched join because you with get a count of resturaunts and the cityid will never be equal with what you are wanting, but there should be a way to get the rusturaunt count without ‘displaying’ it in the sub-query, but again, I forget how to do that.

SELECT TOP 3 …

HTH,
John Barone

SELECT TOP(3) resturantid, co.countryid, ci.cityid FROM r resturant WHERE r.isactive=1
JOIN co country ON r.countryid = co.countryid
JOIN ci city ON r.cityid = ci.cityid
GROUP BY co.countryname, ci.cityname
ORDER BY co.countryname, resturantid, ci.cityid DESC