Comments on: updating char

By: carlosdl

carlosdl — Wed, 06 Jan 2010 00:50:50 +0000

Yes, you get 48, because 48 is the code for the ’0′ character.

Could you please explain why you need to use

SELECT ASCII(REVOKFLG)

instead of simply:

SELECT REVOKFLG

to get 0 as result ?

There is no printable character for the ascii code 0. This code represents the null character, so I can’t think of a way to get 0 when asking for the ascii code of REVOKFLG.

You can use a number stored in a char column as a number (and not as a character) without any problems (and w/o the need of the ASCII function), or you could use a column of type NUMBER(1) if you feel more comfortable with it.

I’m sure there is something that needs clarification here. Please provide as much deatils as possible about your requirement.

By: gunzforlife

gunzforlife — Tue, 05 Jan 2010 22:53:45 +0000

I had tried that earlier which actually made me ask questions about this.
Unfortunately when I checked again by querying ( SELECT ascii(REVOKFLG) from OPERATOR where login like ‘ospprov’;) , REVOKFLG is (48) and not (0).

For this I want to know if there is something I am missing?

By: carlosdl

carlosdl — Tue, 05 Jan 2010 21:15:49 +0000

UPDATE operator 
SET REVOKFLG='0' 
WHERE login like ‘ospprov’;

Am I missing something ?

By: gunzforlife

gunzforlife — Tue, 05 Jan 2010 20:48:40 +0000

Oracle 10g
OPERATOR is the Object
REVOKFLG is a field that’s of CHAR type. either 0 or 1.
I am trying to update the REVOKFLG which is displayed in ascii as ’0′ (flag uncheck).

SQL> update operator set REVOKFLG=char(0) where login like ‘ospprov’;
update operator set REVOKFLG=char(0) where login like ‘ospprov’
*
ERROR at line 1:
ORA-00936: missing expression

Please how can I update this?

By: mrdenny

mrdenny — Tue, 05 Jan 2010 19:55:29 +0000

What database platform are you using?