Comments on: Time Elapsed http://itknowledgeexchange.techtarget.com/itanswers/time-elapsed/ Sat, 26 May 2012 14:45:19 +0000 http://wordpress.org/?v=2.6.2 By: A1maida http://itknowledgeexchange.techtarget.com/itanswers/time-elapsed/#comment-101736 A1maida Tue, 17 Jan 2012 12:15:50 +0000 #comment-101736 Thanks for your help. Thanks for your help.

]]> By: BigKat http://itknowledgeexchange.techtarget.com/itanswers/time-elapsed/#comment-101573 BigKat Thu, 12 Jan 2012 19:45:55 +0000 #comment-101573 Actually, %DIFF returns an integer of the number of FULL units between the 2 values so you will only see 1.00 in your total hour field what you want is to retrieve the minutes divided by 60; [CODE] d total_hours s 9p 2 d time1 s t inz(T'12.00.00') d time2 s t inz(T'13.38.00') /free [B] total_hours = %diff(time2 : time1 : *mn)/60; [/B] dump(a); *inlr = *on; /end-free [/CODE] Actually, %DIFF returns an integer of the number of FULL units between the 2 values

so you will only see 1.00 in your total hour field what you want is to retrieve the minutes divided by 60;

d total_hours     s              9p 2
d time1           s               t   inz(T’12.00.00′)
d time2           s               t   inz(T’13.38.00′)

 /free
     total_hours = %diff(time2 : time1 : *mn)/60;     
     dump(a);
     *inlr = *on;
 /end-free
]]> By: Philpl1jb http://itknowledgeexchange.techtarget.com/itanswers/time-elapsed/#comment-101572 Philpl1jb Thu, 12 Jan 2012 19:41:19 +0000 #comment-101572 %diff(time2 : time1 : *h); *h -- number of hours -- 1 hour %diff(time2 : time1 : *minutes); number of minutes returns not 1.38 but 60 + 38 = 98 Hope this helps Phil %diff(time2 : time1 : *h); *h — number of hours — 1 hour

%diff(time2 : time1 : *minutes); number of minutes
returns not 1.38 but 60 + 38 = 98

Hope this helps
Phil

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