Hi, How can I create a LF using crtlf command based on a particular member in a multimember PF? Where I have to specify the member name?
Answer Question | June 24, 2011 12:23 PM
as/400 files, CRTLF, Logical Files, Physical file members
while creating an object for a logical file we will use in CL/400 CRTLF FILE(library/logical-file-member) SRCFILE(SARKNS/FIVE) But I need to give the logical-file-member name as a field like this pgm Dcl var(&var1) type(*char) len(10) chgvar var(&var1) value(‘logical-file-member’) CRTLF FILE(SARKNS/&var1) SRCFILE(SARKNS/FIVE) endpgm In this case this logical file is not created its giving cpf7302 object not [...]
Answer Question | March 27, 2009 7:43 AM
CL/400, Create Logical File, CRTLF, Logical File