IT Answers » Access 2007 IIf function in a query http://itknowledgeexchange.techtarget.com/itanswers Fri, 24 May 2013 22:16:19 +0000 en-US hourly 1 Access 2007 IIf function in a query http://itknowledgeexchange.techtarget.com/itanswers/access-2007-iif-function-in-a-query/ http://itknowledgeexchange.techtarget.com/itanswers/access-2007-iif-function-in-a-query/#comments Tue, 03 Jan 2012 06:14:16 +0000 Riaane Please excuse my noobness but I am new to Access and rarely work with it.

How do I replace the data in 1 field with the data of another field, if any data exists in the 2nd field? I suspect IIf would be the best way but I get

‘NewID: IIf([OffenderID]=”0000000000000″,[ForeignID],”0000000000000″)’ is not a valid name – error in Access.

My query functoin is:

NewID: IIf([OffenderID]=”0000000000000″,[ForeignID],”0000000000000″)

If my [OffenderID] field = 0000000000000 and the [ForeignID] field is not Null, then the [OffenderID] must be populated with the value in the [ForeignID] field. If the [ForeignID] is Null, then the data in the [OffenderID] field must remain as is.

What am I missing please?

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