Subnetting
Given an IP address range, select the correct subnet mask for the scenario. IP address: 200.4.82.0/24 You need to create 6 networks with a minimum of 28 hosts per network. What is the correct subnet mask and the 3rd subnet range?
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November 2, 2012 7:58 PM
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Given a homework/study type of question, we need to see the work you’ve done or at least the answer you think is correct before we can add much discussion. We can guide or help you to understand obstacles. But we can’t supply direct answers.– Tom
The following answer gives you your 6 networks with enough ip addresses for 28 hosts on each network. So, you correct subnet mask is 255.255.255.224 and the 3rd subnet range is:200.4.82.64 /30 –> Network ID200.4.82.65 /30 –> First Usable Host IP200.4.82.94 /30 –> Last Usable Host IP200.4.82.95 /30 –> Broadcast IP
The following answer gives you your 6 networks…
It’s possible that it will; I didn’t check. But direct answers to homework questions are not appropriate to put into comments. If the OP will not participate in dialog to show a clear business reason for the question, it should be assumed to be homework.
Tom
@Santucci, the /30 CIDR notation should be /27.
yes thats right you will only get 2 host when you use 30 prefixes,,,so the mask should be 27…
Yes you are correct, I meant to put down the /27 as indicated in my 255.255.255.224 subnet mask. The 224 is a /27, so my answer is correct I just somehow put down the wrong /cidr notation. So the only thing that should change in my answer is the /30 to /27. Thanks for catching that Tom.