SELECT
   count(*),days(SYSLCHG)
 FROM mytesttbl
   GROUP BY days(SYSLCHG)
   HAVING count(*)<>0

As does this:

SELECT
   count(*),days(SYSLCHG)
 FROM mytesttbl
   GROUP BY days(SYSLCHG)
   HAVING count(*)<>0
   ORDER BY  1  desc

The first discussion point by ARWinner is on the mark.

Of course, that assumes that TMSTP_COL is a timestamp.

Tom

If GROUP BY or HAVING is used:

• Each column-name in the select list must identify a grouping expression or be specified within a column function:
  • – If the grouping expression is a column name, the select list may apply additional operators to the column name. For example, if the grouping expression is a column C1, the select list may contain C1+1.
  • – If the grouping expression is not a column name, the select list may not apply additional operators to the expression. For example, if the grouping expression is C1+1, the select list may contain C1+1, but not (C1+1)/8.

That last bit — “If the grouping expression is not a column name” — sure makes it sound like a column name is not required. And the example — “the grouping expression is C1+1″ — sure seems to show that a column name isn’t required.

But nothing is said about a SCALAR function either way.

I’ve never figured out the exact rules, so I just do like others have suggested — [DAYS(TMSTP_COL) as NewCol] — in the SELECT list and reference [NewCol] elsewhere.

Tom

select count(*) THECOUNT, X.M_DAYS
FROM (SELECT DAYS(TMSTP_COL) M_DAYS
FROM MYTAB) X
GROUP BY X.M_DAYS
HAVING COUNT(*) > 1
ORDER BY THECOUNT DESC

Stanton

select …. AS NAME …. group by NAME….

SELECT COUNT(*) as quantity, DAYS(TMSTP_COL)
FROM MYTAB A
GROUP BY DAYS(TMSTP_COL)
HAVING COUNT(*) > 1
ORDER BY quantity DESC

or this:

SELECT COUNT(*), DAYS(TMSTP_COL)
FROM MYTAB A
GROUP BY DAYS(TMSTP_COL)
HAVING COUNT(*) > 1
ORDER BY 1 DESC

HTH

Andy