How to parse a string

5 pts.
Tags:
Oracle
Hi, I have a file name that has multiple nodes, I want to get the file extension after the last '.'. How do I do this?

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Use INSTR

DECLARE
v_pos NUMBER;
v_string VARCHAR2(20) := ‘abc.123.txt’;
v_file_type VARCHAR2(20);
BEGIN
v_pos := INSTR(v_string, ‘.’, -1);
v_file_type := SUBSTR(v_string, v_pos + 1);
DBMS_OUTPUT.PUT_LINE(v_file_type);
END;
/

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