how do i select last id in list box and perform a click
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TryingHard
50 pts.
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Q:
how do i select last id in list box and perform a click
Visual Basic, Visual Basic 2008, Visual Basic List Box
I have a list box created that pulls over inner and outer html links from my web page. I have a code to click on the link id within that list and invoke a (click) then the proper function is invoked. my problem is the page changes in number of links ect form hr to hr. but the link i need to click will always be listed at the bottom of the list box.

so one day this code might work...

Private Sub Button5_Click_1(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button5.Click

WebBrowser1.Document.Links(111).InvokeMe...

End Sub


BUT.... the next day the list could be shorter and the link is now at 92. so i get the error that i can only call on 0 thru 92

I cant call on the link by innertext because i have several links with the same text and i would like to keep to calling on links via the list box.
ASKED: Nov 28 2008  5:21 AM GMT
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Carlosdl
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The "length" property sets or retrieves the number of objects in a collection, in this case the "links" collection, so the last link will be the link at the position length - 1.

So I think you could use something like this:


WebBrowser1.Document.Links(WebBrowser1.Document.links.length - 1).InvokeMe...
Last Answered: Nov 28 2008  6:17 PM GMT by Carlosdl   29855 pts.
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TryingHard   50 pts.  |   Nov 28 2008  7:19PM GMT

Your awesome!
That work!

i have another question which is driving me insane! I’m trying to view some code with the x and y value in it. i want to be able to make a mouse click at a pin point location with in a browser. So far i’m coming up empty and wish someone would show a code example, to learn from. I just bought a 80 dollar book on vb 2008 and it only covers this in pieces. But never shows examples to view and learn from. so if anyone has any code that would perform a simple mouse click at a certain point in the browser using the (x)( y) values please share!

 
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