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	<title>Comments on: Dynamic file allocation in a COBOL subroutine</title>
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		<title>By: infosysmgmt</title>
		<link>http://itknowledgeexchange.techtarget.com/itanswers/dynamic-file-allocation-in-a-cobol-subroutine/#comment-79752</link>
		<dc:creator>infosysmgmt</dc:creator>
		<pubDate>Wed, 28 Jul 2010 16:40:31 +0000</pubDate>
		<guid isPermaLink="false">#comment-79752</guid>
		<description><![CDATA[In your first sentence you stated you have successfully coded dynamic file allocation in a COBOL program.  Then you would only have to call that module, passing the necessary parameters i.e. file name, disposition, etc.  The called module would return a return-code indicating success or failure.  In case of success you would proceed as normal in opening, reading, closing your file.  Call the module again to deallocate - free - the file allocation.   At least I remember thats the way I used to do, although the dynamic allocaiton routine was an assembler module.]]></description>
		<content:encoded><![CDATA[<p>In your first sentence you stated you have successfully coded dynamic file allocation in a COBOL program.  Then you would only have to call that module, passing the necessary parameters i.e. file name, disposition, etc.  The called module would return a return-code indicating success or failure.  In case of success you would proceed as normal in opening, reading, closing your file.  Call the module again to deallocate &#8211; free &#8211; the file allocation.   At least I remember thats the way I used to do, although the dynamic allocaiton routine was an assembler module.</p>
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