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	<title>Comments on: DATE CONVERTION</title>
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	<item>
		<title>By: EDG4EVR</title>
		<link>http://itknowledgeexchange.techtarget.com/itanswers/date-convertion/#comment-114648</link>
		<dc:creator>EDG4EVR</dc:creator>
		<pubDate>Thu, 27 Dec 2012 12:07:02 +0000</pubDate>
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		<description><![CDATA[Tom,Thanks for your reply, the standard I&#039;ll be using is the week defined by the aplication.&#160; Those dates will be used only for future forecast, so, those dates don´t have to be a firm dates..Ronaldo]]></description>
		<content:encoded><![CDATA[<p>Tom,Thanks for your reply, the standard I&#8217;ll be using is the week defined by the aplication.&nbsp; Those dates will be used only for future forecast, so, those dates don´t have to be a firm dates..Ronaldo</p>
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	<item>
		<title>By: TomLiotta</title>
		<link>http://itknowledgeexchange.techtarget.com/itanswers/date-convertion/#comment-114510</link>
		<dc:creator>TomLiotta</dc:creator>
		<pubDate>Fri, 21 Dec 2012 21:30:06 +0000</pubDate>
		<guid isPermaLink="false">http://itknowledgeexchange.techtarget.com/itanswers/date-convertion/#comment-114510</guid>
		<description><![CDATA[That depends on the definition of &quot;week&quot; and the standard you use for converting a week number to a day of the year. A &quot;week&quot; could be a calendar week or it could be ISO week (or a &quot;week&quot; defined by the application). And your standard might have weeks starting on Sunday, Monday or any other day. Without knowing your definitions, there&#039;s no way to guess if it&#039;s possible to convert the values. -- Tom]]></description>
		<content:encoded><![CDATA[<p>That depends on the definition of &#8220;week&#8221; and the standard you use for converting a week number to a day of the year. A &#8220;week&#8221; could be a calendar week or it could be ISO week (or a &#8220;week&#8221; defined by the application). And your standard might have weeks starting on Sunday, Monday or any other day. Without knowing your definitions, there&#8217;s no way to guess if it&#8217;s possible to convert the values. &#8212; Tom</p>
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