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	<title>Comments on: Comparing improvement in software response time with its previous version.</title>
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		<title>By: tomliotta</title>
		<link>http://itknowledgeexchange.techtarget.com/itanswers/comparing-improvement-in-software-response-time-wrt-its-previous-version/#comment-102869</link>
		<dc:creator>tomliotta</dc:creator>
		<pubDate>Tue, 14 Feb 2012 07:32:27 +0000</pubDate>
		<guid isPermaLink="false">#comment-102869</guid>
		<description><![CDATA[&lt;i&gt;Is it ((2-4)/2 * 100 = 100% gain) or (4-2/4 * 100 = 50% gain in terms of time saved) ?&lt;/i&gt;

Instead using 4 seconds down to 2 seconds, think about 4 seconds down to 1 second or down to 3 seconds. Plug those numbers in instead of 2 and see what the percentages look like.

If you are thinking of an improvement over 4 seconds, then 2 seconds of new response time means that 2 seconds was trimmed off of the original time. If you have a 4 pound roast and you cut 2 pounds off of it, you cut off 50%.

But if you are thinking of something like throughput, then the rate has increased by 100%. That is, instead of doing one &#039;Login&#039; in 4 seconds, now you can do two. The throughput rate has doubled; or it has increased by 100%.

It&#039;s not so much a matter of your formula as it&#039;s a matter of what you&#039;re measuring.

Tom]]></description>
		<content:encoded><![CDATA[<p><i>Is it ((2-4)/2 * 100 = 100% gain) or (4-2/4 * 100 = 50% gain in terms of time saved) ?</i></p>
<p>Instead using 4 seconds down to 2 seconds, think about 4 seconds down to 1 second or down to 3 seconds. Plug those numbers in instead of 2 and see what the percentages look like.</p>
<p>If you are thinking of an improvement over 4 seconds, then 2 seconds of new response time means that 2 seconds was trimmed off of the original time. If you have a 4 pound roast and you cut 2 pounds off of it, you cut off 50%.</p>
<p>But if you are thinking of something like throughput, then the rate has increased by 100%. That is, instead of doing one &#8216;Login&#8217; in 4 seconds, now you can do two. The throughput rate has doubled; or it has increased by 100%.</p>
<p>It&#8217;s not so much a matter of your formula as it&#8217;s a matter of what you&#8217;re measuring.</p>
<p>Tom</p>
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