Comparing improvement in software response time with its previous version.

5 pts.
Tags:
Performance Measurement
Software response time
Hi,
I have a question, which looks silly but I am getting different opinion among our stake holders.  I need to report an improved performance in our new version of software, where the total time required for for a functionality, say 'Login' in new version takes 2 seconds where as it takes 4 seconds in our previous version.  
Now, how do I present this in terms of percentage improvement in performance?  Is it ((2-4)/2 * 100 = 100% gain) or (4-2/4 * 100 = 50% gain in terms of time saved) ?
Pls note : This is comparison of same software between two versions and not b/w two different products.  So, is there any rule on which one should go to denominator?.
Any articles you can point me to?


Software/Hardware used:
Manual Testing
ASKED: February 14, 2012  6:59 AM
UPDATED: February 27, 2012  8:45 PM

Answer Wiki

Thanks. We'll let you know when a new response is added.
Send me notifications when members answer or reply to this question.

REGISTER or login:

Forgot Password?
By submitting you agree to receive email from TechTarget and its partners. If you reside outside of the United States, you consent to having your personal data transferred to and processed in the United States. Privacy

Discuss This Question: 1  Reply

 
There was an error processing your information. Please try again later.
Thanks. We'll let you know when a new response is added.
Send me notifications when members answer or reply to this question.

REGISTER or login:

Forgot Password?
By submitting you agree to receive email from TechTarget and its partners. If you reside outside of the United States, you consent to having your personal data transferred to and processed in the United States. Privacy
  • TomLiotta
    Is it ((2-4)/2 * 100 = 100% gain) or (4-2/4 * 100 = 50% gain in terms of time saved) ? Instead using 4 seconds down to 2 seconds, think about 4 seconds down to 1 second or down to 3 seconds. Plug those numbers in instead of 2 and see what the percentages look like. If you are thinking of an improvement over 4 seconds, then 2 seconds of new response time means that 2 seconds was trimmed off of the original time. If you have a 4 pound roast and you cut 2 pounds off of it, you cut off 50%. But if you are thinking of something like throughput, then the rate has increased by 100%. That is, instead of doing one 'Login' in 4 seconds, now you can do two. The throughput rate has doubled; or it has increased by 100%. It's not so much a matter of your formula as it's a matter of what you're measuring. Tom
    125,585 pointsBadges:
    report

Forgot Password

No problem! Submit your e-mail address below. We'll send you an e-mail containing your password.

Your password has been sent to:

To follow this tag...

There was an error processing your information. Please try again later.

REGISTER or login:

Forgot Password?
By submitting you agree to receive email from TechTarget and its partners. If you reside outside of the United States, you consent to having your personal data transferred to and processed in the United States. Privacy

Thanks! We'll email you when relevant content is added and updated.

Following