C++ scope resolution operator tell the output and give the reason
#include<iostream.h> #include<conio.h> int a=10; void main() { int a=5; clrscr();
cout<<::a++<<++a<<endl; for(int i=1;i<=3;i++) { cout<<a++<<::a+2;
getch(); }
}
Software/Hardware used:
turbo C++
cout<<::a++<<++a<<endl; for(int i=1;i<=3;i++) { cout<<a++<<::a+2;
getch(); }
}
Software/Hardware used:
turbo C++
ASKED:
March 14, 2010 6:27 PM
UPDATED:
July 6, 2010 9:28 PM
Answer Wiki:
the answer to the above problem must be:
106
613713813
solution:
cout<<::a++<<++a;
it prints 10 and increments the global a value by one and increments local a value and prints it 6
inside loop
cout<<a++<<::a+2;
first execution
6 13 since a++ prints 6 and increments = 6+1 = 7 , ::a+2 = 11+2
second execution
7 13 a++ prints 7 and increments = 7+1 = 8, ::a+2 = 11+2 since scope a is not incremented
third execution
8 13 same type of calculation
so the o/p is
106
613713813
tel me if correct
To see all answers submitted to the Answer Wiki: View Answer History.
You should run the code and analyze the output to get the answer.
You are correct Nsn.
Usually, we don’t answer this kind of question here, as it is clearly a homework assignment, and giving the answer to the OP is not going to help him (her).