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	<title>Irregular Expressions &#187; heap overflow</title>
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	<description>Insight into current security related events and exploits, including virtualization security and tips.</description>
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		<title>MS10-025 And Buffer Overflows</title>
		<link>http://itknowledgeexchange.techtarget.com/Irregular-Expressions/ms10-025-and-buffer-overflows/</link>
		<comments>http://itknowledgeexchange.techtarget.com/Irregular-Expressions/ms10-025-and-buffer-overflows/#comments</comments>
		<pubDate>Mon, 26 Apr 2010 04:08:48 +0000</pubDate>
		<dc:creator>Dan O'Connor</dc:creator>
				<category><![CDATA[buffer]]></category>
		<category><![CDATA[buffer overflow]]></category>
		<category><![CDATA[CVE-2010-0478]]></category>
		<category><![CDATA[heap overflow]]></category>
		<category><![CDATA[ms01-025]]></category>
		<category><![CDATA[stack overflow]]></category>

		<guid isPermaLink="false">http://itknowledgeexchange.techtarget.com/Irregular-Expressions/?p=228</guid>
		<description><![CDATA[The MS10-025 update has been retracted, MS states that it &#8220;does not address the underlying issue&#8221; . MS10-025 is a Windows Server 2000 SP4 Windows media services Stack-based buffer overflow. Both are the same concept, but Stack vs Heap referrers to where the overflow occurred. A Heap overflow takes place in a dynamically allocated section [...]]]></description>
				<content:encoded><![CDATA[<p>The MS10-025 update has been retracted, MS states that it &#8220;does not address the underlying issue&#8221; .</p>
<p>MS10-025 is a Windows Server 2000 SP4 Windows media services Stack-based buffer overflow. Both are the same concept, but Stack vs Heap referrers to where the overflow occurred.</p>
<p>A Heap overflow takes place in a dynamically allocated section of memory, for those of you that can understand c it would be a variable crated with the &#8220;malloc&#8221; function. Heap memory is allocated at run time ( dynamic ).</p>
<pre>char *buff = malloc(10);</pre>
<p>Stack overflows take place in static variables ( set at compile time ). Again if you can read c and if you cannot this will look familiar.</p>
<pre>char buff[10];</pre>
<p>Either one is exploited by the same technique, sending more data then the buffer can hold.</p>
<p>Here is the technical write up at US-Cert.</p>
<p>http://www.us-cert.gov/cas/techalerts/TA10-103A.html</p>
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